Integrand size = 21, antiderivative size = 66 \[ \int \frac {\sin ^3(c+d x)}{(a+a \sec (c+d x))^2} \, dx=\frac {2 \cos (c+d x)}{a^2 d}-\frac {\cos ^2(c+d x)}{a^2 d}+\frac {\cos ^3(c+d x)}{3 a^2 d}-\frac {2 \log (1+\cos (c+d x))}{a^2 d} \]
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Time = 0.20 (sec) , antiderivative size = 66, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {3957, 2915, 12, 78} \[ \int \frac {\sin ^3(c+d x)}{(a+a \sec (c+d x))^2} \, dx=\frac {\cos ^3(c+d x)}{3 a^2 d}-\frac {\cos ^2(c+d x)}{a^2 d}+\frac {2 \cos (c+d x)}{a^2 d}-\frac {2 \log (\cos (c+d x)+1)}{a^2 d} \]
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Rule 12
Rule 78
Rule 2915
Rule 3957
Rubi steps \begin{align*} \text {integral}& = \int \frac {\cos ^2(c+d x) \sin ^3(c+d x)}{(-a-a \cos (c+d x))^2} \, dx \\ & = \frac {\text {Subst}\left (\int \frac {(-a-x) x^2}{a^2 (-a+x)} \, dx,x,-a \cos (c+d x)\right )}{a^3 d} \\ & = \frac {\text {Subst}\left (\int \frac {(-a-x) x^2}{-a+x} \, dx,x,-a \cos (c+d x)\right )}{a^5 d} \\ & = \frac {\text {Subst}\left (\int \left (-2 a^2+\frac {2 a^3}{a-x}-2 a x-x^2\right ) \, dx,x,-a \cos (c+d x)\right )}{a^5 d} \\ & = \frac {2 \cos (c+d x)}{a^2 d}-\frac {\cos ^2(c+d x)}{a^2 d}+\frac {\cos ^3(c+d x)}{3 a^2 d}-\frac {2 \log (1+\cos (c+d x))}{a^2 d} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.77 \[ \int \frac {\sin ^3(c+d x)}{(a+a \sec (c+d x))^2} \, dx=\frac {-22+27 \cos (c+d x)-6 \cos (2 (c+d x))+\cos (3 (c+d x))-48 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )}{12 a^2 d} \]
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Time = 0.96 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.73
method | result | size |
derivativedivides | \(\frac {\frac {\cos \left (d x +c \right )^{3}}{3}-\cos \left (d x +c \right )^{2}+2 \cos \left (d x +c \right )-2 \ln \left (\cos \left (d x +c \right )+1\right )}{d \,a^{2}}\) | \(48\) |
default | \(\frac {\frac {\cos \left (d x +c \right )^{3}}{3}-\cos \left (d x +c \right )^{2}+2 \cos \left (d x +c \right )-2 \ln \left (\cos \left (d x +c \right )+1\right )}{d \,a^{2}}\) | \(48\) |
parallelrisch | \(\frac {24 \ln \left (\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )+34+\cos \left (3 d x +3 c \right )-6 \cos \left (2 d x +2 c \right )+27 \cos \left (d x +c \right )}{12 a^{2} d}\) | \(53\) |
norman | \(\frac {\frac {10 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{d a}+\frac {14}{3 a d}+\frac {12 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{d a}}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{3} a}+\frac {2 \ln \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )}{a^{2} d}\) | \(90\) |
risch | \(\frac {2 i x}{a^{2}}+\frac {9 \,{\mathrm e}^{i \left (d x +c \right )}}{8 a^{2} d}+\frac {9 \,{\mathrm e}^{-i \left (d x +c \right )}}{8 a^{2} d}+\frac {4 i c}{a^{2} d}-\frac {4 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{a^{2} d}+\frac {\cos \left (3 d x +3 c \right )}{12 d \,a^{2}}-\frac {\cos \left (2 d x +2 c \right )}{2 d \,a^{2}}\) | \(107\) |
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Time = 0.27 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.73 \[ \int \frac {\sin ^3(c+d x)}{(a+a \sec (c+d x))^2} \, dx=\frac {\cos \left (d x + c\right )^{3} - 3 \, \cos \left (d x + c\right )^{2} + 6 \, \cos \left (d x + c\right ) - 6 \, \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right )}{3 \, a^{2} d} \]
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Timed out. \[ \int \frac {\sin ^3(c+d x)}{(a+a \sec (c+d x))^2} \, dx=\text {Timed out} \]
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Time = 0.19 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.77 \[ \int \frac {\sin ^3(c+d x)}{(a+a \sec (c+d x))^2} \, dx=\frac {\frac {\cos \left (d x + c\right )^{3} - 3 \, \cos \left (d x + c\right )^{2} + 6 \, \cos \left (d x + c\right )}{a^{2}} - \frac {6 \, \log \left (\cos \left (d x + c\right ) + 1\right )}{a^{2}}}{3 \, d} \]
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Time = 0.31 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.14 \[ \int \frac {\sin ^3(c+d x)}{(a+a \sec (c+d x))^2} \, dx=-\frac {2 \, \log \left ({\left | -\cos \left (d x + c\right ) - 1 \right |}\right )}{a^{2} d} + \frac {a^{4} d^{2} \cos \left (d x + c\right )^{3} - 3 \, a^{4} d^{2} \cos \left (d x + c\right )^{2} + 6 \, a^{4} d^{2} \cos \left (d x + c\right )}{3 \, a^{6} d^{3}} \]
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Time = 0.07 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.85 \[ \int \frac {\sin ^3(c+d x)}{(a+a \sec (c+d x))^2} \, dx=-\frac {\frac {2\,\ln \left (\cos \left (c+d\,x\right )+1\right )}{a^2}-\frac {2\,\cos \left (c+d\,x\right )}{a^2}+\frac {{\cos \left (c+d\,x\right )}^2}{a^2}-\frac {{\cos \left (c+d\,x\right )}^3}{3\,a^2}}{d} \]
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